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Quant – Mixture & Allegation – Set 4
Read the following instructions carefully
- The test contains 10 questions.
- Each question has 4 options, of which only one is correct.
- You have to finish the test in 8 minutes.
- You are awarded 1 mark for each correct answer, and 0.25 marks are deducted for each wrong answer.
- There is no negative marking for questions you do not attempt.
- You may pause the test at any time and resume where you left off.
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Review this set's questions and answers (opens after you submit the test)
This free practice set from AndamanJobs has 10 questions to be solved in 8 minutes. Every question is listed below with four options. Open Show answer and explanation under a question to see the correct option and why it is correct. Try the timed test above first, then use this list to revise the questions you got wrong.
- Two vessels A and B contains acid and water in the ratio 4:3 and 5:3 respectively. Then the ratio in which these mixtures to be mixed to obtain a new mixture in vessel C containing acid and water in the ratio 3:2 is :
- A. 7:5
- B. 4:7
- C. 7:8
- D. 5:8
Show answer and explanation
Answer: C. 7:8
Acid fraction: A = 4/7, B = 5/8, required = 3/5. A : B = (5/8 - 3/5) : (3/5 - 4/7) = 1/40 : 1/35 = 7 : 8.
- Two containers have acid and water mixed respectively in the ratio 3:1 and 5:3.To get a new mixture with ratio of acid to water as 2:1, the two types have to be mixed in the ratio ?
- A. 2:1
- B. 3:2
- C. 1:2
- D. 2:3
Show answer and explanation
Answer: C. 1:2
Acid fraction: first = 3/4, second = 5/8, required = 2/3. First : second = (2/3 - 5/8) : (3/4 - 2/3) = 1/24 : 1/12 = 1 : 2.
- Acid and water are mixed in a vessel A in the ratio of 5:2 and in the vessel B in the ratio 8:5. In what proportion should quantities be taken out from the two vessels so as to form a mixture in which the acid and water will be in the ratio of 9:4?
- A. 7:4
- B. 2:7
- C. 7:2
- D. 2:3
Show answer and explanation
Answer: C. 7:2
Acid fraction: A = 5/7, B = 8/13, required = 9/13. A : B = (9/13 - 8/13) : (5/7 - 9/13) = 1/13 : 2/91 = 7 : 2.
- The ratio of spirit and water in two mixtures of 20 liters and 36 litres is 3:7 and 7:5 respectively. Both the mixtures are mixed together. Now the ratio of the spirit and water in the new mixture is :
- A. 27:29
- B. 25:29
- C. 9:10
- D. 27:31
Show answer and explanation
Answer: A. 27:29
Spirit = 3/10 × 20 + 7/12 × 36 = 6 + 21 = 27 L. Water = 56 - 27 = 29 L. Ratio = 27 : 29.
- Two vessels A and B contain acid and water mixed in the ratio 2:3 and 4:3. In what ratio must these mixtures be mixed to form a new mixture containing half acid and half water?
- A. 7:5
- B. 2:1
- C. 5:7
- D. 1:2
Show answer and explanation
Answer: C. 5:7
Acid fraction: A = 2/5, B = 4/7, required = 1/2. A : B = (4/7 - 1/2) : (1/2 - 2/5) = 1/14 : 1/10 = 5 : 7.
- Alcohol and water in two vessels A and B are in the ratio 5:3 and 5:4 respectively. In what ratio, the liquids in both the vessels be mixed to obtain a new mixture in vessel C in the ratio 7:5?
- A. 2:3
- B. 3:2
- C. 3:5
- D. 2:5
Show answer and explanation
Answer: A. 2:3
Alcohol fraction: A = 5/8, B = 5/9, required = 7/12. A : B = (7/12 - 5/9) : (5/8 - 7/12) = 1/36 : 1/24 = 2 : 3.
- A vessel is filled with liquid ,3 parts of which are water and 5 parts are syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and syrup ?
- A. 1/7
- B. 1/3
- C. 1/4
- D. 1/5
Show answer and explanation
Answer: D. 1/5
Water is 3/8 of the vessel. After removing a fraction f and adding water: (3/8)(1 - f) + f = 1/2, so 5f/8 = 1/8 and f = 1/5.
- A container contains 60 kg of milk. From this container 6kg of milk was taken out and replaced by water. This process was repeated further two times. The amount of milk left in the container is :
- A. 34.24 kg
- B. 43.74 kg
- C. 47.9 kg
- D. 39.64 kg
Show answer and explanation
Answer: B. 43.74 kg
Milk left = 60 × (54/60)³ = 60 × 0.729 = 43.74 kg.
- In two types of stainless steel , the ratio of chromium and steel are 2:11 and 5:21 respectively. In what proportion should the two types be mixed so that the ratio of chromium to steel in the mixed type becomes 7:32 ?
- A. 1:3
- B. 2:3
- C. 1:2
- D. 3:4
Show answer and explanation
Answer: C. 1:2
Chromium fraction: first = 2/13, second = 5/26, required = 7/39. First : second = (5/26 - 7/39) : (7/39 - 2/13) = 1/78 : 1/39 = 1 : 2.
- A and B are two alloys of gold and copper in the ratio 7:2 and 7:11 respectively. If equal quantities of these two alloys are melted to from a new alloy C, then the ratio of gold and copper in C is :
- A. 12:7
- B. 9:4
- C. 7:5
- D. 6:5
Show answer and explanation
Answer: C. 7:5
Gold in A = 7/9 and in B = 7/18. Equal quantities: gold = (7/9 + 7/18)/2 = 7/12, so copper = 5/12. Ratio = 7 : 5.